--- /dev/null
+---
+title: "Why even unused data needs to be valid"
+categories: rust
+---
+
+`unsafe` code in Rust has a few ways that it can trigger [Undefined Behavior][ub], i.e., there are a few assumptions that the compiler makes about all code, and that for `unsafe` code the programmer is responsible for upholding.
+Those assumptions are [listed in the Rust reference](https://doc.rust-lang.org/reference/behavior-considered-undefined.html).
+The one that seems to be most surprising to many people is the clause which says that unsafe code may not produce "[...] an invalid value, even in private fields and locals".
+The reference goes on to explain that "*producing* a value happens any time a value is assigned to or read from a place, passed to a function/primitive operation or returned from a function/primitive operation".
+In other words, even just *constructing*, for example, an invalid `bool`, is Undefined Behavior---no matter whether that `bool` is ever actually "used" by the program.
+The purpose of this post is to explain why.
+
+[ub]: https://rust-lang.github.io/unsafe-code-guidelines/glossary.html#undefined-behavior
+
+<!-- MORE -->
+
+First of all, let me clarify what is meant by "used" here, as that term is used to mean very different things.
+The following code "uses" `b`:
+
+{% highlight rust %}
+fn example(b: bool) -> i32 {
+ if b { 42 } else { 23 }
+}
+{% endhighlight %}
+
+I hope it is not very surprising that calling `example` on, e.g., `3` transmuted to `bool` is Undefined Behavior (UB).
+When compiling `if`, the compiler assumes that `0` and `1` are the only possible values; there is no saying what could go wrong when that assumption is violated.
+
+What is less obvious is why calling `example` on `3` is UB even when there is no such `if` being executed.
+To understand why that is important, let us consider the following example:
+
+{% highlight rust %}
+fn example(b: bool, num: u32) -> i32 {
+ let mut acc = 0;
+ for _i in 0..num {
+ acc += if b { 42 } else { 23 };
+ }
+ acc
+}
+{% endhighlight %}
+
+Now assume we were working in a slightly different version of Rust, where transmuting `3` to a `bool` is fine as long as you do not "use" the `bool`.
+That would mean that calling `example(transmute(3u8), 0)` is actually allowed, because in that case the loop never gets executed, so we never "use" `b`.
+
+However, this is a problem for a very important transformation called [loop-invariant code motion](https://en.wikipedia.org/wiki/Loop-invariant_code_motion).
+That transformation can be used to turn our `example` function into the following:
+
+{% highlight rust %}
+fn example(b: bool, num: u32) -> i32 {
+ let mut acc = 0;
+ let incr = if b { 42 } else { 23 }
+ for _i in 0..num {
+ acc += incr;
+ }
+ acc
+}
+{% endhighlight %}
+
+The increment `if b { 42 } else { 23 }` is "invariant" during the execution of the loop, and thus computing the increment can be moved out.
+Why is this a good transformation?
+Instead of determining the increment each time around the loop, we do that just once, thus saving a lot of conditional jumps that the CPU is unhappy about.